What happens when two charged spheres are brought into contact?

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When two identical charged metal spheres come into contact, charge redistribution occurs until equilibrium is reached. Sphere A, initially at +5q, and sphere B, at -q, will share their charges. After contact, sphere A will have a charge of +2q, while sphere B will have a charge of +2q as well. This redistribution results in both spheres having the same charge of +2q. Understanding this process is crucial for grasping electrostatic principles.
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When a metal sphere, A, with a charge of +5q is touched to a sphere,B, with a charge of -q what would each of the spheres charge would be and what would there the circle view of the final sphere?

thanks
 
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Hello Gyoza06,

Welcome to Physics Forums!

Gyoza06 said:
When a metal sphere, A, with a charge of +5q is touched to a sphere,B, with a charge of -q what would each of the spheres charge would be and what would there the circle view of the final sphere?

thanks

Could you rewrite the problem? I'm not sure how to interpret it. Is sphere A the same size as sphere B? What do you mean by "circle view" and "final" sphere?

Also, please let us know what you think the answer is and why. You must show us that you have attempted the problem before we can help. :smile:
 
ya sorry I am new to this but the spheres are identical and by final circle view i mean the picture diagram used to show the charge take place with a circle with either + or - signs indicating the charge. if i messed this up again i apologize.
 
my solution is sphere A ends up with a charge of +2.5q and sphere B ends up with a charge of +1.5q
 
Gyoza06 said:
my solution is sphere A ends up with a charge of +2.5q and sphere B ends up with a charge of +1.5q

You should rethink your answer. If the conducting spheres are identical in size and shape, and there is a charge difference between them, current will flow from one sphere to the other if they are touching (thus changing the charge on each sphere) until equilibrium is reached.
 
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