Charge & Energy Stored in Charged Capacitor (14V, 113pF)

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The discussion revolves around calculating the charge and energy stored in a capacitor with a capacitance of 113 pF and a voltage of 14 V. The charge on the capacitor is calculated using the formula Q = C * U, resulting in 1.582 µC. For energy storage, the formula E = 1/2 * C * U^2 gives an energy of 11.074 µJ. However, participants note that the calculations must account for the conversion of picofarads to farads, as 1 pF equals 1 × 10^-12 F. Accurate unit conversion is crucial for obtaining correct results in capacitor calculations.
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Homework Statement


A voltage of 14 V is placed on a capacitor with C = 113 pF (picofarads).

(a) What is the charge on the capacitor?

(b) How much energy is stored in the capacitor?

I believe I have the correct equation but I'm not sure about the final answer because of the picofarads. Are my answers correct?

Homework Equations



(a)Q=C*U
(b)E,stored=1/2*C*U^2

The Attempt at a Solution


(a)113*14=1.582e-6
(b)113*14^2*(1/2)=11.074e-6
 
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Your units are off by a few orders of magnitude.

1 picofarad = 1 × 10-12 Farads
 
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