Charge on a cavity wall and Gauss' law

AI Thread Summary
The discussion revolves around calculating the charge on the cavity wall and the outer surface of an isolated conductor with a net charge of +14.0 × 10^-6 C and a particle of charge +4.30 × 10^-6 C inside a cavity. It is clarified that the charge on the cavity wall must be equal in magnitude but opposite in sign to the charge of the particle, resulting in a charge of -4.30 × 10^-6 C on the cavity wall. The total charge on the outer surface is then derived by adding the cavity wall charge to the net charge of the conductor, resulting in +18.3 × 10^-6 C. The confusion about the charge within the Gaussian shell is addressed, emphasizing that the net charge inside the conductor remains zero. Understanding these principles is essential for correctly applying Gauss' law in this context.
Jrlinton
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Homework Statement


An isolated conductor has a net charge of +14.0 × 10- 6 C and a cavity with a particle of charge q = +4.30 × 10-6 C. What is the charge (a) on the cavity wall and (b) on the outer surface?

Homework Equations

The Attempt at a Solution


So I understand that B is just adding the charge of the particle and conductor together
=1.8E-5C
I am lost on the solution to part A. I thought that the charge on or within the cavity wall of a gaussian shell was zero but that doesn't seem to be the answer they are looking for
 
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Jrlinton said:
I am lost on the solution to part A. I thought that the charge on or within the cavity wall of a gaussian shell was zero but that doesn't seem to be the answer they are looking for
Imagine a Gaussian surface within the conducting material that encloses the cavity. What's the total charge?
 
the net charge is zero so the charge on the wall is the negative of the particle charge within
 
Jrlinton said:
the net charge is zero so the charge on the wall is the negative of the particle charge within
Exactly.
 
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