Charge on Cylinder Shell: Q1 + Q2

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The discussion revolves around calculating the charges on the interior and exterior surfaces of a coaxial conducting cylindrical shell surrounding a charged rod. The rod has a net charge of Q1 = +3.67 × 10-12 C, while the shell has a charge of Q2 = -2.04Q1. The charge on the interior surface of the shell will equal -Q1 to maintain electrostatic equilibrium, while the exterior surface charge will be the sum of Q1 and Q2. Participants suggest using Gauss's law to analyze the electric field between the rod and the shell. Understanding these principles is crucial for solving the problem accurately.
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Homework Statement


The figure is a section of a conducting rod of radius R1 = 1.60 mm and length L = 11.30 m inside a thin-walled coaxial conducting cylindrical shell of radius R2 = 10.5R1 and the (same) length L. The net charge on the rod is Q1 = +3.67 × 10-12 C; that on the shell is Q2 = -2.04Q1.

What is the charge on the interior and exterior surface of the shell?

Picture inserted below.

Homework Equations


I have no idea.

The Attempt at a Solution


I don't even know how to start this. I know the answer of the charge on the exterior is the sum of Q1 and Q2, but I don't know how where the answer came from.
 

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Hello RF,
Guidelines don't like 'dunno' but I'll give you a hint: what about the ##\vec E## field between inner and outer R2 ? And: learn about Gauss already ?
 

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