Electric field lines are just a graphic means to visualize the electric field. So if there is an electric field, field lines can be used to illustrate it.Intle said:If I have an electric field between a cathode and an anode, are there electric field lines between the plates?
What do you think? What does the direction of a field line represent?Intle said:If yes, what happens if a charged particle enters the field at an angle? Is the force acting on the particle reduced?
I apologize for not being specific enough. I am asking this question because when looking at the magnetic fields and particle motion withing that field the equation, F=q*v*B*sin() can be used to take into account the particle's initial velocity vector hitting the magnetic force vector at an angle. I am wondering if there is a similar equation for electric fields since the only equation I have found so far is F=E*q which to my understanding basically just says that it does not matter if there is an initial velocity or not and/or at what angle the charged particle hits the field.lychette said:get clear in your mind what is meant by an electric field. You have an ANODE and a CATHODE...which direction is the electric field (assuming the anode and cathode are connected to the appropriate power supply)
what does this tell you about FORCES on charged particles?
Correct, it does not matter, the force is always the same.Intle said:the only equation I have found so far is F=E*q which to my understanding basically just says that it does not matter if there is an initial velocity or not and/or at what angle the charged particle hits the field.
So why is that different in a magnetic field?mfb said:Correct, it does not matter, the force is always the same.
Intle said:So why is that different in a magnetic field?
Intle said:So why i
So why is that different in a magnetic field?
Yes, thank you for your answers.ZapperZ said:I think that you are utterly confused about the Lorentz force law.
There are TWO parts to this force law, as can be seen from the two separate terms in it:
F = qE + q v x B
Your question, i.e. a charge moving in between two plates (assuming uniform electric field), involves NO external magnetic field. So here, only
F = qE
is relevant. This problem is no different than, say, a projectile motion in a uniform gravity (i.e. first year intro physics).
Is this clear?
Zz.
The angle at which a charged particle enters an electric field determines the direction and magnitude of its motion. The particle will experience a force in the direction of the electric field, causing it to accelerate. The angle will determine the component of the force in the direction of the electric field, and therefore, the direction of the particle's motion.
The speed of a charged particle will increase or decrease depending on the angle at which it enters the electric field. If the angle is perpendicular to the electric field, the particle's speed will remain constant. However, if the angle is at any other angle, the particle's speed will change as it accelerates due to the force of the electric field.
The charge of a particle does not directly affect its motion when it enters an electric field at an angle. However, the charge will determine the strength of the force it experiences in the electric field, which will then affect the particle's motion. A higher charge will result in a stronger force and therefore a greater acceleration.
Yes, the mass of a charged particle does affect its motion in an electric field at an angle. The greater the mass of the particle, the more inertia it will have, and the more difficult it will be to change its direction and speed. This means that a particle with a larger mass will be less affected by the force of the electric field and will therefore have less acceleration.
The angle at which a charged particle enters an electric field is directly related to the strength of the force it experiences. The force acting on the particle will be strongest when the angle is perpendicular to the electric field, and it will decrease as the angle deviates from perpendicular. This is because the perpendicular component of the force, which is responsible for the particle's acceleration, decreases as the angle becomes less perpendicular.