Check my work please? Circuit analysis, resistors in parallel, help

AI Thread Summary
The discussion revolves around verifying circuit analysis involving resistors in parallel and the correct application of sign conventions for power calculations. The user expresses uncertainty about the signs of power for sources and resistors, particularly questioning if the power of the 60V source should be negative. Clarification is provided that while the power supplied by the source is negative, the power dissipated in the resistors is positive, adhering to the passive sign convention. The equation for power balance is confirmed as Power in source + Power in load = 0. Ultimately, the user resolves their confusion regarding the power dissipation in resistors R3 and R4.
nchin
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Can someone check my work for me please? I'm pretty sure i made a mistake with the sign convention but I'm not sure which sources are supposed to be negative. help!

Problem:
http://imageshack.us/a/img201/339/circuitzz.png

My solution:
http://imageshack.us/a/img191/8049/circuitz.png

The top half is me solving the left side the circuit and the bottom half is the right side of the circuit.
 
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The basic calculations/magnitude look fine to me. However the passive convention says that the power of the sources would be negative. So for example the power of the 60V source is -0.6W.

Examples..
http://circuits.solved-problems.com/456/problem-1-15-power-independent-sources/
 
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so if the power of the 60v source is -0.6, does that mean the power in resistor 1 is -0.1 and the power in resisor 2 is -0.5? since power supplied = power dissipated?? (-0.6 = -0.1 + (-0.5))?
 


ok nvm i figured it out,, but am i solving r3 and r4 correctly?
 


nchin said:
so if the power of the 60v source is -0.6, does that mean the power in resistor 1 is -0.1 and the power in resisor 2 is -0.5? since power supplied = power dissipated?? (-0.6 = -0.1 + (-0.5))?

No the power dissipated in the resistors is +ve. You write something like..

Power in source + Power in load = 0

-0.6 + 0.1 + 0.5 = 0
 


I threw away the scrap paper I used yesterday but yes I got the same power disipation as you for R3 and 4.
 
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