Checking if Three Operators Form a 3-Vector with SO(3) Commutation Relations

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Discussion Overview

The discussion revolves around the examination of three operators defined in spherical coordinates to determine if they form a 3-vector that satisfies the SO(3) commutation relations. The focus is on the mathematical properties and transformations of these operators within the context of angular momentum in quantum mechanics.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents three operators and claims they satisfy the SO(3) commutation relations.
  • Another participant suggests that to prove the operators form a vector, one should show how they transform under rotations, indicating that the operators are already in the form of angular momentum operators.
  • A later reply indicates that while the transformation from Cartesian to spherical coordinates has been shown, there is uncertainty about how to assign these operators to specific components of a vector in spherical coordinates.
  • There is a request for clarification on determining the corresponding components of the operators in (r, θ, φ) coordinates.

Areas of Agreement / Disagreement

Participants express differing views on the assignment of the operators to specific vector components, indicating that the discussion remains unresolved regarding the exact correspondence of the operators in spherical coordinates.

Contextual Notes

There are limitations regarding the assumptions made in the transformation process and the definitions of the operators in different coordinate systems, which have not been fully resolved.

jfy4
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Hello,

Lets say I have three operators

[tex]k_3=\partial_\phi[/tex], [tex]k_1=\sin\phi\partial_\theta+\cot\theta\cos\phi\partial_\phi[/tex], [tex]k_2=\cos\phi\partial_\theta-\cot\theta\sin\phi\partial_\phi[/tex].

These operators satisfy the SO(3) commutation relations:

[tex][k_i,k_j]=\epsilon_{ijk}k_k[/tex]

How can I check to see if these three operators together form a 3-vector?
 
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In general you prove a set of operators Vi form a vector by showing how they transform under rotations, namely [Li, Vj] = eijk Vk. But in this case, your operators Vi already are Li!

I think what I'd do is to start out by defining Li in Cartesian coordinates, Lz = x∂y - y∂x, etc, transform them to spherical coordinates and show they reduce to your Vi. That substantially proves it.
 
Bill_K said:
In general you prove a set of operators Vi form a vector by showing how they transform under rotations, namely [Li, Vj] = eijk Vk. But in this case, your operators Vi already are Li!

I think what I'd do is to start out by defining Li in Cartesian coordinates, Lz = x∂y - y∂x, etc, transform them to spherical coordinates and show they reduce to your Vi. That substantially proves it.

Ok, I have managed to show that they come from the Cartesian coordinates, however, It still does not seem to me that these 3 operators are specifically assigned to anyone component of a vector. That is,

[tex]L_x=z\partial_y-y\partial_z[/tex]

but after the transformation

[tex]L_x=\sin\phi\partial_\theta+\cot\theta\cos\phi\partial_\phi[/tex]

What component would this correspond to in [tex](r,\theta,\phi)[/tex] coordinates? How can I determine what component these three operators correspond too?
 
bump.
 

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