- #1
lonewolf219
- 186
- 2
Hi, I'm wondering how to integrate 4xe^(4x).
I got:
4[1/4xe^(4x)-1/16e^(4x)+c] ?
which reduces to
xe^(4x)-1/4e^(4x)+c
Is this the correct integral?
Thanks.
I got:
4[1/4xe^(4x)-1/16e^(4x)+c] ?
which reduces to
xe^(4x)-1/4e^(4x)+c
Is this the correct integral?
Thanks.