ChemE: vapor pressure and condensation

AI Thread Summary
The discussion revolves around determining the condensation temperature of carbon tetrachloride (CCl4) in a gaseous mixture with dry air. The initial conditions are set at 62.0°C and 1141 mmHg, with a mol fraction of 0.190 for CCl4. To find the temperature at which 56.0% of the CCl4 condenses, the user needs to calculate the moles of CCl4 that condense and the remaining gas phase composition. The partial pressure of CCl4 in the gas phase must be established to determine the equilibrium temperature at that vapor pressure. The challenge lies in understanding how to apply the relevant equations and concepts to solve for the desired temperature.
GreatEscapist
Messages
178
Reaction score
0

Homework Statement


A gaseous mixture containing 0.190 mol fraction of carbon tetrachloride (CCl4) and 0.810 mol fraction of dry air is initially at 62.0°C and 1141 mmHg. If this mixture is cooled at a constant pressure, at what temperature does the CCl4 first start to condense? I already did this problem

At what temperature would 56.0% of the CCl4 condense?

Homework Equations


Partial pressure = p*(T)
log10(p*)= A + (B/(T+C))
I'm sure there are more I'm supposed to use

The Attempt at a Solution



After solving for the original problem, for the second, I know that I need to find how many moles are condensed...but I don't know how to do that. Or what to do after that, or with that information.
 
Physics news on Phys.org
Not sure how the dry air enters the problem, but disregarding that, once the CCl4 starts to condense, it is impossible to further reduce the temperature of the (two) CCl4 phases at constant pressure until the CCl4 is saturated liquid. That should answer your question ...
 
GreatEscapist said:

Homework Statement


A gaseous mixture containing 0.190 mol fraction of carbon tetrachloride (CCl4) and 0.810 mol fraction of dry air is initially at 62.0°C and 1141 mmHg. If this mixture is cooled at a constant pressure, at what temperature does the CCl4 first start to condense? I already did this problem

At what temperature would 56.0% of the CCl4 condense?

Homework Equations


Partial pressure = p*(T)
log10(p*)= A + (B/(T+C))
I'm sure there are more I'm supposed to use

The Attempt at a Solution



After solving for the original problem, for the second, I know that I need to find how many moles are condensed...but I don't know how to do that. Or what to do after that, or with that information.

Take as a basis one mole of gas. Then the number of moles of CCl4 is 0.19, and the number of moles of air is 0.81. If 56% of the CCl4 condenses, how many moles of CCl4 liquid is formed, and how many moles of CCl4 remain in the gas phase? What is the total number of moles remaining in the gas phase (air plus CCl4)? At that point, what is the mole fraction of CCl4 in the gas phase? Since the total pressure remains 1141 mm Hg, what is the partial pressure of CCl4 in the gas phase? What is the equilibrium temperature at this vapor pressure of CCl4?
 
Back
Top