Chemical Equilibrium Constant Calculation

AI Thread Summary
To calculate the equilibrium constant (Keq) for the reaction C(s) + O2(g) → CO2(g) at 25°C, the relationship between Gibbs free energy change (dGorxn) and Keq is essential. The provided Gibbs free energy of formation for CO2 is -394.36 kJ/mol, while the values for C(s) and O2(g) are zero. The equation dGorxn = -R*T*ln(Keq) is used, but the user initially calculated an incorrect value for Keq. Clarification on the significance of the reaction quotient (Q) and its relationship to Keq is also sought, indicating confusion about the concepts involved.
hotwheelharry
Messages
8
Reaction score
0

Homework Statement



If Q = 1.0 1042 for the reaction C(s) + O2(g) → CO2(g) at 25°C, calculate Keq.

dGof (Kj/mol) of...
C(s)=0
O2(g)=0
CO2(g)=-394.36

Homework Equations


dGorxn = -R*T*ln(K)

The Attempt at a Solution



-394.36*1000 = -8.314472(298)ln(K)
K=1.3e69

This is the wrong answer. I'm lost as to what to do. Please help.
I might be using the wrong equation for the situation. The only information I was given was in the problem statement.
 
Last edited:
Physics news on Phys.org
What is Q? How is it related to Keq?
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
Back
Top