Chemical Kinetics Qn: Why is D Not a Possible Answer?

AI Thread Summary
The discussion centers on the effects of doubling the initial volume of SO2 on the production of SO3 and the resulting pressure, confirming that this leads to higher pressure, as indicated by answer C. There is confusion regarding why option D is not valid; while increasing temperature does enhance the reaction rate, it also alters the equilibrium composition, affecting the pressure of SO3. The graph does not reflect a higher pressure for SO3 at increased temperatures, which is attributed to changes in the equilibrium state. The horizontal asymptote of the reaction will shift based on whether the reaction is endothermic or exothermic. Overall, the interplay between volume, temperature, and equilibrium composition is crucial in understanding the observed results.
nicholaschean
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The correct answer states its C which i understand why since doubling the intiial volume of SO2 is equivilent to doubling the intial moles of SO2 hence the moles of SO3 produced will also increase and hence pressure exerted shld be higher than before which is not reflected by the graph.

However, why is D not a possible answer? When temperature increases, the reactant particles will gain energy and cause rate of reaction to increase which is reflected by the graph here. But the SO3 particles produce will also be more active compared to lower temperature in experiment 1, hence shouldn't it exert a higher pressure than experiment 1? which in this case is not shown on the graph.
 
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nicholaschean said:
FCpTz.jpg


The correct answer states its C which i understand why since doubling the intiial volume of SO2 is equivilent to doubling the intial moles of SO2 hence the moles of SO3 produced will also increase and hence pressure exerted shld be higher than before which is not reflected by the graph.

However, why is D not a possible answer? When temperature increases, the reactant particles will gain energy and cause rate of reaction to increase which is reflected by the graph here. But the SO3 particles produce will also be more active compared to lower temperature in experiment 1, hence shouldn't it exert a higher pressure than experiment 1? which in this case is not shown on the graph.

Increasing the temperature will change the equilibrium composition, and your sulfur trioxide pressure would have a different horizontal asymptote.

The asymptote will move up or down depending on whether the reaction is endothermic or exothermic.

Note that increasing temperature WILL increase the rate of reaction.
 
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