Chemistry: Hot-Air Ballon Oxygen Storage

AI Thread Summary
To determine the total volume of pressure vessels needed for a hot-air balloon trip requiring 1,206,900 liters of oxygen, the calculations involve converting liters to psi using Boyle's law. At 40,000 feet, the pressure changes, necessitating adjustments in volume calculations. The maximum pressure of 4500 psi from carbon-fiber wrapped bottles must be considered, with 1 psi equating to approximately 0.0703 kg/cm. The discussion emphasizes the need to derive the volume of compressed air required at both 40,000 feet and sea level. Accurate conversions and understanding of gas laws are crucial for solving the problem effectively.
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Homework Statement



Given that 1,206,900 liters of oxygen are required for a round-the-world trip for a hot-air balloon with a crew of three, and given that carbon-fiber wrapped bottles have a maximum pressure of approx 4500 psi, what total volume of pressure vessel would be necessary to bring along adequate compressed air for the flight? If the bottles come in volumes of 12ft^3, how many bottles does this represent? The balloon flies at an altitude of 40,000 feet. Find these values for 40,000 ft and 0 ft (sea level.)

Homework Equations



This question comes across as a standard Chemistry conversion. Air weighs 1.3 grams per liter. 1 psi is equal to .0703 Kg/cm, so 4500 psi equals 316.38 kg/cm.

The Attempt at a Solution



The question seems to be asking me to convert liters to psi, but I can't figure out how to do that, even when I try converting liter to kg/cm.
 
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Use Boyle's law. P1V1 = P2V2

For P1 use 1 atm (what is that in psi?). You know V1 and P2 as well. Can you derive V2?
 
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