Chemistry Lab Homework: Reaction Rates & Concentration Calculation

AI Thread Summary
The discussion focuses on calculating the concentration of acetic acid (CH3COOH) in a chemistry lab involving vinegar. The user is attempting to determine the concentration using the formula c = n*v, where they need to find the number of moles (n) based on the mass (m) and molar mass (M). Clarification is sought regarding whether the volume of 0.02L refers to pure acetic acid or vinegar, which is 3% acetic acid by weight. The conversation emphasizes the importance of understanding the definitions of variables in the equations used. Accurate concentration calculation is essential for the lab experiment's success.
Revengeance
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Homework Statement


Hello all, I am doing this lab http://scc.scdsb.edu.on.ca/Students/onlinecourses/Sikora/sch4u/v12/60.pdf

i am stuck on trying to find hte concentration of ch3cooh

Homework Equations


n = m / M and c = n*vand i think the ideal gas law could be used but not sure

The Attempt at a Solution


so the volume of ch3cooh for the first trial is 0.02L, and in order to find the concentration i must find the moles
 
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Revengeance said:
concentration of ch3cooh
If you are told "vinegar" is three per cent acetic acid by weight, does that help?
Revengeance said:
n = m / M and c = n*v
You're going to have to tell us what these letters mean; we aren't mind readers.
Revengeance said:
so the volume of ch3cooh for the first trial is 0.02L, and in order to find the concentration i must find the moles
Twenty milliliters of vinegar at three per cent? Or twenty milliliters of acetic acid?
 
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