Calculating N2O4 Reaction Rate in 4L Container

[Nanu Nana]

Homework Statement

N2O4 --------------> NO2 N2O4 for k = 0.050 s-1
The process starts from 0.20 mole of N2O4 in a container of 4.0L. Calculate v for N2O4.
if 3/4 of the N2O4 is converted

Homework Equations

To calculate concentration
c= mole/L

The Attempt at a Solution

0.20 mole /4.0 L =0.05 M
(3/4)x0.05 =0.0375 M
V(reaction rate) = k .0.0375M
v= 0.050 s-1 x 0.0375 M
v=0.001875
But the answer should be 6.3x10^-4 [/B]

 

[Borek]

How much is left

if 3/4 of the N2O4 is converted

?

 

[Suraj M]

if 3/4 of the N2O4 is converted

How did you arrive at this?

 

[Borek]

How did you arrive at this?

That's a given.