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Hemolymph
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Homework Statement
50.0 mL sample of 2.0 10–4 M CuNO3 is added to 50.0 mL of 4.0 M NaCN. The formation constant of the complex ion Cu(CN)3 is 1.0 10^9. What is the copper(I) ion concentration in this system at
equilibrium?
The Attempt at a Solution
I did a dilution and got the new concentrations of Cu and CN to be 1x10^-4M for copper
and 2M for CN
Then Cu+3CN→Cu(CN)_3
I (1.0x10^-4)(2)
C
E
Not sure how to proceed