Engineering Circuit Analysis of driven RC Circuit with short circuits

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The discussion focuses on analyzing a driven RC circuit with a short circuit and determining current and voltage at specific time intervals. At t=0+, the current through the circuit is 0.1 A, resulting in a voltage of 20 V across a 200-ohm resistor and the capacitor. The voltage across the capacitor remains at 20 V at t=0 due to the inability to change instantaneously. There is confusion regarding whether to include the 200-ohm resistor in the circuit analysis and whether the circuit can be considered source-free. Theoretical insights suggest that while ideal resistors can change voltage or current instantaneously, real resistors exhibit slight capacitive and inductive properties that affect this behavior.
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Homework Statement


Determine the value of the current labeled i and the voltage labeled v at t=0+, t= 1.5 ms, and t = 3.0 ms.

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Homework Equations


Ohm's law: v = i *r
Decay in source free RC Circuit v(t) = v@0 * e^(-t/RC)

The Attempt at a Solution


i(0-) = 0.1 A.
Therefore,
v across 200 ohm = 200* 0.1 = 20 V
Since no current flows through capacitor with constant dc current,
v across capacitor = 20 V @ t < 0

v across capacitor cannot change immediately as it would require infinite power so v across capacitor @ t = 0 = 20 V

Here's where the confusion is: Should I include the 200 ohm resistor in my RC circuit? Why or why not? Also, will my circuit be a source free RC circuit?

Also, what will be the current i through the 200 ohm resistor when t>0?

My last question is a theoretical one: Can a current through a resistor change immediately at one instant of time?
 
Last edited:
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200Ω in parallel with a short circuit (0Ω) is 0Ω (a short circuit).

Theoretically, an ideal resistor can experience an immediate change of voltage across it or current through it. However, all real resistors will have tiny capacitive/inductive characteristics.
 

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