Engineering Circuit Simplification, did I do this right?

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The circuit simplification presented appears correct, but there is confusion regarding the use of ohms for all components, which complicates understanding impedance. The discussion highlights the importance of recognizing that the book is currently simplifying concepts for easier comprehension. A question arises about calculating Vb using the Voltage Divider Rule, with confirmation that the approach is correct but requires careful attention to parentheses in the formula. However, it is noted that merely rearranging components does not fulfill the requirement to combine impedances and currents as specified in the assignment. Overall, the focus remains on ensuring proper calculations and understanding of circuit simplification.
Jordash
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I have a circuit here:

Circuit.jpg


And I simplified it like so:

simplifiedCircuit.jpg


Did I do it correctly?

Thanks,

Jordan
 
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It looks right. Why are all components in ohms? That makes my head hurt.
 
I'm glad it's right, The book tries to simplify things by adding the ohms to help us realize that impedance is similar to ohms when the book get's more complicated it shows the actual capacitance. So I guess the book is kind of in "Training Wheels" mode at the moment :)
 
Oh and Quick question about Calculating Vb I know that I can use the Voltage Divider Rule to get it (I did that for Va)

For Vb would I use the total impedance of all the impedances above the 820 ohms as say Z1 and then the impedance of the 820 Ohm resistor so it would be Vb=V* (820ohms/Z1+820Ohms) <-- VDR

Is my thinking right?
 
Yes. But watch your parens: Vb = V * (820 / (z1 +820)), which is probably what you meant.
 
Oh yeah your right, thanks for catching that.
 
That isn't what they meant by simplifying the circuit, though.

You just moved the components around on the page.

You need to work out the combined impedances and the currents as asked for in the question.
 

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