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## Homework Statement

the switch in the circuit is closed at t=0 for a very long time.

find the current across the 2 ohm resistor before the switch is closed.

find the current across the 5 ohm resistor before the switch is closed.

find the current across the 2 ohm resistor RIGHT at t=0.

find the current across the 5 ohm resistor RIGHT at t=0.

explain why the current across the 2 ohm resistor at 0- is equal to 0+

explain why the current across the 5 ohm resistor at 0- is not equal to 0+

here is the circuit i made in LTSpice (and a little with paint):

http://img528.imageshack.us/img528/2843/724ds9.jpg [Broken]

## Homework Equations

when the switch is open, everything to the right of the switch isin parallel with the switch... everything to the right of the switch is shunted when the switch is closed. the circuit is really then, two seperate circuits.

ohm;s law:

V=iR

relationship btwn current, voltage, and capacitance:

i=C(dV/dt)

KVL and KCL

## The Attempt at a Solution

this is as far as i have gotten:

i used (for the left side of the circuit when the switch is closed):

V4=i(R4)

R4 = 1 volt / 20 ohms = 0.05 amps

so, when the switch was open, the initial current through R3====>

0.1amps + 0.05 amps = 0.15 amps

the right side of the circuit is a voltage divider when the switch is closed

While the switch is open, the capacitor fully charges up to 1 volt. right at t=0, there is no instantanious change in voltage, therefore dV/dt = 0 therefore current through the capacitor is also 0.

any ideas?

(btw is there a way to make this image smaller without having to re-upload it?)

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