Circuits - Power and Resistivity

AI Thread Summary
The discussion focuses on calculating the length of a Nichrome wire used in a heating coil with a power rating of 530 W at 110 V. The initial calculations yield a resistance of 22.83 ohms, leading to an estimated wire length of approximately 4.07 meters based on the resistivity of Nichrome at 20°C. However, the user suspects an error in their calculations, as they believe the answer is incorrect, and mentions discrepancies in resistivity values found on Wikipedia. Additionally, they express uncertainty about whether the teacher may have made a miscalculation. The conversation highlights the complexities of electrical resistance and the importance of accurate resistivity values in such calculations.
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Homework Statement


A 530 W heating coil designed to operate from 110 V is made of Nichrome wire 0.500 mm in diameter.
(a) Assuming that the resistivity of the Nichrome remains constant at its 20.0°C value, find the length of wire used.
(b) If the diameter of the wire were doubled, how long would the wire be if it had the same resistance?

My chart says rhoNichrome=1.1E-6

Homework Equations


P=VI
V=IR
rho=R(A/l)
A=pi*r^2

The Attempt at a Solution


0.5/2=0.25 (radius)
pi*(0.25)^2=0.196mm^2 = A

V=IR => I=V/R
P=V(V/R) => 530=110^2/R
R=22.83 ohms

1.1E-6=22.83(0.196E-6/l)
l=~4.07m

But this answer is wrong. If someone could help me find my mistake in part A, I can work part B. Thanks!
 
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Looks okay to me. Wikipedia has rhoNichrome= 1.5 E-6 ohm-meter
 
That gave me 2.98m and 11.95m. Both were still wrong. Hmmm. It's possible my teacher made a miscalculation, she does that fairly frequently. Thank you though!
 
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