Circuits Question - Voltage and current in an inductor circuit

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SUMMARY

The discussion focuses on calculating the equivalent impedance (Zeq) in an inductor circuit with a direct current (DC) source. The user has determined that there are 2 Amps entering the circuit and has derived the equation for Zeq as Z_{eq} = \frac{<(arctan(\frac{R}{ωL}))}{ω^{2}L^{2}+R^{2}}. Given that the frequency (f) is 0, the user simplifies this to Z_{eq} = \frac{j}{R^{2}}. The voltage across the inductor is expressed as vL(t) = 120e-2500t, while the current through the inductor is iL(t) = 2 + 6e-2500t.

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Circuits Question -- Voltage and current in an inductor circuit

Homework Statement



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Homework Equations


The Attempt at a Solution



I found Zeq and there are exactly 2 Amps going into it. I'm not sure what to do from here.

[itex]Z_{eq} = \frac{<(arctan(\frac{R}{ωL}))}{ω^{2}L^{2}+R^{2}}[/itex]

I'm not sure what to do from here, thanks for any help.
 

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Ok so because this is DC

ω = 2∏f

but f= 0

so

[itex]Z_{eq} = \frac{j}{R^{2}}[/itex]

Where do I go from here?
 


vL(t) = 120e-2500t

iL(t) = 2 + 6e-2500t

Claude
 

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