MHB Circular Functions: Sec-1(-rad(2))

[rebecca120]

Sec^-1(-rad(2))

 

[CaptainBlack]

Sec^-1(-rad(2))

Please supply more context, like the question as asked.

The argument of \( \rm{asec} \) is just a number so I don't see what \( \rm{rad} \) is doing in your question.

CB

 

[HallsofIvy]

Sec^-1(-rad(2))

-rad(2)? Do you mean "- 2 radians"? Use the fact that sec(x)= 1/cos(x) and use a calculator (making sure it is in "radian" mode) to find cos^{-1}(-1/2).

Or do you mean "radical(2)" as in "\sqrt{2}"? \frac{1}{\sqrt{2}}= \frac{\sqrt{2}}{2} so find cos^{-1}\left(-\frac{\sqrt{2}}{2}\right). You shouldn't need a calculator for that.