Circular motion and parabolic orbit

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SUMMARY

The discussion focuses on the dynamics of a point object of mass m connected to an inertialess string of length L, moving in a vertical plane. The object, starting with an initial speed v0, experiences a transition to a parabolic orbit after reaching point B, where the tension in the string becomes zero. Key equations derived include the speed at point B as √(gL sin θ), the initial speed as √((2 + 3 sin θ)gL), and the height H reached as v² cos² θ / 2g. The participants seek solutions for the angles at points C and the relationship between the object's velocity and the horizontal direction.

PREREQUISITES
  • Understanding of circular motion dynamics
  • Knowledge of gravitational potential energy and kinetic energy principles
  • Familiarity with trigonometric functions and their applications in physics
  • Ability to analyze motion in a vertical plane
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  • Study the principles of centripetal force in circular motion
  • Learn about energy conservation in mechanical systems
  • Explore projectile motion and its equations
  • Investigate the relationship between velocity and angle in parabolic trajectories
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Students of physics, particularly those studying mechanics, educators teaching circular motion concepts, and anyone interested in the dynamics of objects in motion under gravitational influence.

shrrikesh
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Homework Statement



A point object of mass m is connected to an inertialess string of length L, the other end of which is connected to a fixed point O. At time t=0, the object is assumed to move horizontally in a vertical plane from the bottom point A (OA=L). in the clockwise direction with an initial speed v0 as seen in the figure.

http://img208.imageshack.us/img208/5223/figure.jpg

If [tex]\sqrt{2gL}[/tex]<v0<[tex]\sqrt{5gL}[/tex], then at a point B (the angle between OB and the horizontal direction is designated [tex]\theta[/tex]) the magnitude of the force acting on the object from the string becomes zero, where OB=L and the velocity is perpendicular to OB. v being the magnitude of the vector velocity. If 0<[tex]\theta[/tex]<[tex]\pi[/tex]/2.

1) the speed v is given by...?

2) the initial speed is ...?

3) From the point B, for a while, the object takes a parabolic orbit till C where OC=L . The maximum elevation (with respect to location B) is expressed as ...?

4) In the case [tex]\theta[/tex]=[tex]\pi[/tex]/3, the angle [tex]\phi[/tex] measured as in fig. specifying the point C becomes. ...?

5) and finally the angle , the angle between the object velocity at the point C and the horizontal direction is ...?

Homework Equations



for no 1)

mv2/L-mgsin(90+[tex]\theta[/tex]) = 0

for no 2)

decrease in Kinetic Energy = Gain in Potential Energy

for no 3)

H = v2sin2(90-[tex]\theta[/tex])/2g

I am not able to do for no 4 and 5.

The Attempt at a Solution


I've found out the answers for question 1,2 and 3 which are

[tex]\sqrt{gLsin\theta}[/tex], [tex]\sqrt{(2+3sin\theta)gL}[/tex] and v2cos2[tex]\theta[/tex]/2g respectively.

I don't have any ideas to solve the last two ones.
 
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