How Fast Must a Turntable Spin to Slide a Bug Off?

Thread starter neoking77
Start date Mar 21, 2006
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Bug Circular Circular motion Motion

AI Thread Summary

To determine the RPM needed for a bug to slide off a turntable, the coefficient of friction is crucial, with a value of 0.55 in this case. The bug's distance from the center is 25 cm, which affects the centrifugal force required to overcome friction. The frictional force must equal the centripetal force for the bug to remain on the turntable. The user initially struggled with the calculations but later figured out the solution. Understanding the relationship between friction and centripetal force is key to solving this problem.

Mar 21, 2006

neoking77

If the coefficient of friction between a bug and the turntable is 0.55 and the bug is 25 cm from the centre, how fast (in RPM) does the turntable have to spin to cause the bug to slide off?

All I know so far is that the frictional force must be 0 (?)
Fc = m4pi^2r/T^2
but this obviously can't work if Ff is 0...so what am I doing wrong?
thanks in advance

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Mar 21, 2006

neoking77

hey nvm i got it :)

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