Circular Motion Force at Point A: Stunt Car on Frictionless Track

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SUMMARY

The discussion centers on calculating the force exerted by a stunt car on a frictionless track at point A, with a radius of 9.9 m and a mass of 1800 kg. The required speed at the top of the loop is critical for determining the force at point A. The car's velocity was calculated to be 13.4 m/s, but the user struggled with applying the correct physics principles, particularly regarding the conditions at the top of the loop and the implications of a frictionless surface. The solution involves using conservation laws to find the necessary speed and subsequently the force at point A.

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  • Familiarity with conservation of energy principles
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Homework Statement


In the figure, a stunt car driver negotiates the frictionless track shown in such a way that the car is barely on the track at the top of the loop. The radius of the track is 9.9 m and the mass of the car is 1800 kg. Find the force of the car on the track when the car is at point A

http://session.masteringphysics.com/problemAsset/1107086/1/7.10.jpg"

Homework Equations



Accelaration(radius) V2/R F=ma


The Attempt at a Solution



massxacceleration =1800kg x V2/9.9m ... v2=1800kg/9.9 =181 .. v=13.4 m/s

F=1800kg x (13.4)2/9.9

Can someone help me please.. what am I doing wrong?
 
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Is the loop vertical? Is the car traveling on an inclined slope?
 
sorry for the confusion i included a picture link for the problm
 
If the track is frictionless then his trajectory is ballistic; he can't use the engine to accelerate because the tires have no friction with the track.

The condition posed is that the car is "barely on the track at the top of the loop". So work out its required speed there. Then use whatever conservation laws spring to mind.
 

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