Circular Motion Help: 10kg Mass at 3m/sec in 3m Radius

AI Thread Summary
A 10 kg mass traveling at 3 m/sec enters a circular path with a radius of 3 m. The initial calculations for the speed at the bottom of the circular region and the normal force are questioned, with results of 12 m/s and 52 N, respectively. Participants in the discussion clarify that the speed at the bottom can be determined using conservation of energy principles, while the normal force requires consideration of centripetal force and gravitational force. Correct formulas involve calculating kinetic energy and applying Newton's second law. Accurate solutions are essential for understanding the dynamics of circular motion in this scenario.
Cougar1112
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A 10 kg mass is traveling along a track at 3 m/sec. It enters a circular region of radius 3m.

1. what is its speed at the bottom of the circular region?( I got 12 m/s)
2. what is the normal force at the bottom?( I got 52 N)

Right or wrong and if wrong what's the correct solutions/formulas to use.

THANKYOU to whoever helps!
 
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Again, please describe the problem in more detail and provide your work, not just your answers.
 

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