Circular Motion Homework: Angular Velocity, Acceleration, Force Calculation

AI Thread Summary
The discussion revolves around a homework problem involving a grinding wheel with a diameter of 0.12 cm spinning at 1200 RPM. The calculations for angular velocity yield 2400π rad/s, with an angular acceleration of 14.4π m/s² and a force of 1.44 x 10^-3 π N acting on a particle of mass 1 x 10^-4 kg. For part (b), the radial force of 2.5 N leads to an angular velocity of approximately 2041.241 rad/s at which the particle would leave the wheel. In part (c), the speed of the particle upon leaving the wheel is calculated to be 12.247 m/s, with the direction of motion being tangential to the wheel's edge. The calculations are confirmed to be correct, with a note on ensuring proper unit conversions.
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Homework Statement


A grinding wheel has a diameter of 0.12 cm and spins horizontally at 1200 revolutions per minute about a vertical axis. A particle of mass 1 x 10-4 kg sticks to the wheel.

a. calculate the magnitude of the angular velocity, acceleration and force acting on the particle

b. the radial force that keeps the particle on the wheel is 2.5 N. calculate the angular velocity at which the particle leave the wheel.

c. if the wheel exceeds the angular speed in (b), calculate the speed and direction of motion of the particle just after it leaves the surface of the wheel.

Homework Equations


circular motion

The Attempt at a Solution


a.

\omega = 2\pi f = 2400\pi rad/s

a=\omega ^2 r = 14.4 \pi ms^2

F = ma = 1.44 x 10^{-3} \pi Nb.

F=m \omega ^2r

\omega ^2=\frac{2.5}{mr}

\omega= 2041.241 ~rad/sc.

v=\omega r=12.247 ms^{-1}

Direction of motion : tangential to the point where it leavesDo I get it right?

Thanks
 
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Assuming the particle is sticked to the very edge of the disk.

a) Check you angular velocity. the units is rad/s. and unit for the frequency is rev/min
 
Hi estalas

Aah my bad, forgot to change the unit. how about (b) and (c)? Are they correct?

Thanks
 
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