Circular Motion- Just a few quick questions

AI Thread Summary
The discussion revolves around two physics problems related to circular motion. The first problem involves calculating the radius of a spinning chamber based on the force experienced by a person inside, with the initial calculations being incorrect due to a misidentification of mass. The second problem focuses on a car negotiating a circular turn and the impact of reduced friction on the car's speed, requiring the application of static friction and centripetal force equations. Participants suggest writing separate equations for the conditions on dry and wet roads to find the new safe speed. The conversation emphasizes the need for careful attention to detail in problem-solving and the correct application of physics principles.
alex7298
Messages
27
Reaction score
0

Homework Statement


The first problem is "at an amusement park there is a ride in which cylinrically shaped chamber spin around a central axis. People si in seats facing the axis, their backs against the outer wall. At one instant the outer wall moves at a speed of 3.2m/s and an 83kg person feels a 560N force pressing against his back. What is the radius of the chamber?




Second question- "A car is safely negotiating an unbanked circular turn at a speed of 21m/s. The maximum static frictional force actson the tires. Suddenly there is a wet patch in the road reduces the maximum static frictional force by a factor of three. If the car is to continue safely around the curve, to what speed must the driver slow the car?



Homework Equations



For the first problem, i used Fc=mv^2/r
so r=mv^2/Fc...r=(38kg)(3.2m/s^2)/560N=.69, but the answer should be between 1-2. Where am i going wrong?




The Attempt at a Solution



I have no idea where to start for the second question
 
Physics news on Phys.org
nvm about the first question. i just realized i put 38kg instead of 83.

now i only need help on the second
 
the only equations that i can think of that are of any relevance are
Uk=Fk/Fn
Fc=mv^2/r
and that's about it...but i don't know where to start because the only thing it gives you is velocity
 
To negotiate the unbanked curve Fk must be equal to Fc. In both the cases Fn remains constant. Wright down two equations for dry road and wet patch and solve for v.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top