Circular motion of a car and curve

In summary: I'm not sure I understand the question. Are you asking for the number of revolutions after a certain amount of time, or the time it takes to complete a certain number of revolutions?In summary, we have a car accelerating on a curve with a radius of 110m at a constant tangential acceleration of 1.50m/s^2. The magnitude of the total acceleration is 3.20m/s^2. To find the number of revolutions, we can use the standard constant acceleration equations, substituting θ ω and α for s v and a. The units for the acceleration are m/s^2 and the car is constrained to follow a circular path, making it the tangential acceleration.
  • #1
pankti_ptl
5
0
A car starts from rest on a curve with a radius of 110 and accelerates at 1.50 . How many revolutions will the car have gone through when the magnitude of its total acceleration is 3.20 ?





 
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  • #2
Hi pankti_ptl, welcome to PF.
What are the units of radius and acceleration?
The problems is based on circular motion. What are relevant equation you know about circular motion?
 
  • #3
redius in meters and acceleration in m/s^2
 
  • #4
Welcome to PF!

Hi pankti_ptl! Welcome to PF! :smile:

(is the 1.5 a constant tangential acceleration? or is it angular acceleration? :confused:)

Just use the same constant acceleration equations as for linear motion, but with θ ω and α instead of s v and a. :wink:
 
  • #5
it says it is magnitude of total acceleration is 3.20 i dunt kno if its tangental or angular can can we diffrensiate
 
  • #6
and for 1.5 it only says acceleration
 
  • #7
pankti_ptl said:
and for 1.5 it only says acceleration

As rl.bhat :smile: says, what are the units??
 
  • #8
A car starts from rest on a curve with a radius of 110m and accelerates at 1.50m/s^2 . How many revolutions will the car have gone through when the magnitude of its total acceleration is 3.20m/s^2 ?
 
  • #9
pankti_ptl said:
A car starts from rest on a curve with a radius of 110m and accelerates at 1.50m/s^2 . How many revolutions will the car have gone through when the magnitude of its total acceleration is 3.20m/s^2 ?

ok, so the units are m/s2.

And if the car is constrained to follow a circle (a curve of fixed radius), then this is the tangential acceleration.

So convert 1.5 m/s2 into angular acceleration (α), and then use the standard constant acceleration equations, for θ ω and α.
 

What is circular motion?

Circular motion is a type of motion in which an object moves along a circular path. It involves both a constant speed and a change in direction, resulting in a continuously changing velocity.

How does a car move in a circular path?

In order for a car to move in a circular path, it needs to have a centripetal force acting on it. This force is directed towards the center of the circular path and keeps the car from moving in a straight line. This force can be provided by the friction between the car's tires and the road.

What is the relationship between speed and radius in circular motion?

The speed of an object in circular motion is directly proportional to the radius of its path. This means that as the radius decreases, the object's speed increases, and vice versa. This relationship is described by the equation v = ωr, where v is the linear speed, ω is the angular velocity, and r is the radius of the circular path.

How does a car maintain its speed while turning a curve?

When a car is turning a curve, it experiences a centripetal force that is provided by the friction between its tires and the road. This force helps to maintain the car's speed by constantly changing its direction and preventing it from sliding out of the curve.

Why do cars need to slow down when turning a sharp curve?

The tighter the curve, the greater the centripetal force needed to keep the car moving in a circular path. If the car is moving too fast, the friction between the tires and the road may not be enough to provide this force, causing the car to slide out of the curve. Therefore, it is important for cars to slow down when turning sharp curves to maintain control and prevent accidents.

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