Circular motion of stone and rope

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Homework Help Overview

The problem involves a 2.00-kg stone attached to a 4m long rope, which is being whirled in a horizontal circle on a frictionless surface, completing 5 revolutions in 2 seconds. The discussion centers around calculating the tension in the rope and understanding the dynamics of circular motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the nature of the problem, questioning whether it resembles a conical pendulum scenario. They explore the concepts of speed and centripetal acceleration, with some expressing uncertainty about the existence of these quantities in the given context.

Discussion Status

There is an ongoing exploration of the relationship between angular speed, linear speed, and centripetal acceleration. Some participants have provided guidance on converting angular speed to linear speed and applying the formula for centripetal acceleration, while others express skepticism about the presence of speed in the scenario.

Contextual Notes

Participants are navigating the implications of the problem setup, including the absence of friction and the specific conditions of motion. There is a noted confusion regarding the definitions and calculations related to speed and acceleration in circular motion.

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1. a 2.00-kg stone attached to a rope 4m long is whirled in a circle horizontally on a frictionaless surface, completing 5 revolutions in 2s. calculate the magnitude of tension in the rope



2. delta t = 2pie root square l cost theta/g or f= 1/2pie root square g/ l cos theta



3. is the a conical pendulum question?
 
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The stone is on a frictionless surface on a horizontal table, so this is not a conical pendulum problem. There is only one force acting on it in the horizontal (centripetal)direction. What is the stone's speed and centripetal acceleration?
 
apparently there is no speed or centripetal acceleration
 
The stone is being whirled, so it must have a speed. It is given that its angular speed is 2.5 revolutions per second. You can convert that to an angular speed in radians per second, or a linear tangential speed in meters per second, and solve for the centripetal acceleration using what formula for centripetal acceleration?
 
mv^2/r
 
PhanthomJay said:
The stone is being whirled, so it must have a speed. It is given that its angular speed is 2.5 revolutions per second. You can convert that to an angular speed in radians per second, or a linear tangential speed in meters per second, and solve for the centripetal acceleration using what formula for centripetal acceleration?

lol seriously there is no speed
 
That's the formula for centripetal force : Fc =mv^2/r, where r and m are given, so you need to find v, the tangential speed of the stone.
 

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