Cirular Motion - car on a circular ramp

AI Thread Summary
A 1200 kg car traveling at 5 m/s on a circular ramp with a 10 m radius requires the calculation of the normal force exerted by the ramp. The initial attempt to solve this resulted in an incorrect normal force of 15,000 N. Participants noted the importance of considering the direction of forces, particularly at the top of the ramp where gravitational force and centripetal acceleration interact. Clarification was provided that the car's position affects the forces acting on it, leading to confusion about the correct answer. Ultimately, the discussion emphasizes the need to carefully analyze forces in circular motion scenarios.
Fatima Hasan
Messages
315
Reaction score
14

Homework Statement


A 1200 kg car has a speed of 5 m/s at the top of a circular ramp of 10 m in radius. The normal force exerted by the seat of the ramp on the car is :
A) 9000N B) 9600 N C)11250 N D)13650 N E)14150 N

Homework Equations


∑F=ma
ac = m v^2 /r

The Attempt at a Solution


I tried to answer this question but the problem is I don't know where I made the mistake. This is my tried :
∑F = ma = m v^2 /r = N - mg
N = 1200 * 5^2 / 10 + 1200*10
N = 15000 N
So can you check please if it's correct or not ?
Thank you.
 
Physics news on Phys.org
Fatima Hasan said:

Homework Statement


A 1200 kg car has a speed of 5 m/s at the top of a circular ramp of 10 m in radius. The normal force exerted by the seat of the ramp on the car is :
A) 9000N B) 9600 N C)11250 N D)13650 N E)14150 N

Homework Equations


∑F=ma
ac = m v^2 /r

The Attempt at a Solution


I tried to answer this question but the problem is I don't know where I made the mistake. This is my tried :
∑F = ma = m v^2 /r = N - mg
N = 1200 * 5^2 / 10 + 1200*10
N = 15000 N
So can you check please if it's correct or not ?
Thank you.
It is not correct. Check the direction of the individual forces.
 
ehild said:
It is not correct. Check the direction of the individual forces.

Does this question look right to you?
 
  • Like
Likes ehild
ehild said:
It is not correct. Check the direction of the individual forces.
Got it . Thank you
 
Fatima Hasan said:
Got it . Thank you
My answer would be ##0N##. But that's not an option!

Sorry, I just realized the car is on top of the ramp! I wonder how it got there?
 
Last edited:
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top