Classical Mechanics - finding displacement with given force

AI Thread Summary
The discussion revolves around solving a classical mechanics problem involving a particle with a given force equation. The force acting on a 3 kg particle is defined as F = (v/9)(3 - x²), with initial conditions of x = 1 m and v = 0 m/s at t = 0 s. Participants express confusion over integrating the force equation, particularly regarding the treatment of x as a function of time. There are attempts to change variables and set up integrals, but challenges arise due to the non-constant nature of x. The conversation emphasizes the need to correctly handle the integration of x terms to find the displacement at t = 5 s.
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Homework Statement


- The force acting on a particle m = 3kg is given by the following force equation: F = (v/9)(3 - x2),
the particle begins at a position of x = 1m with a speed of v = 0 m/s at time t = 0s. Find the displacement of the particle at time t = 5 s.

Homework Equations


F = m(dv/dt) or F= m(dv/dx)(v)

The Attempt at a Solution


Our professor set up the problem wrong, so he said all we have to do is get to the integral where we'd find x and stop.
 
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Welcome to PF;
... so what did you do?
 
Simon Bridge said:
Welcome to PF;
... so what did you do?
Well I tried it two ways, neither of which I thought was right...
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In the first page, you cannot take the x's outside the integral over t because x is a function of time.
On the second page, you, instead, tried changing the variable ... that seems reasonable to me.
You'll end up with an implicit equation for x(t) but you only need x at a particular time.
 
Simon Bridge said:
In the first page, you cannot take the x's outside the integral over t because x is a function of time.
On the second page, you, instead, tried changing the variable ... that seems reasonable to me.
You'll end up with an implicit equation for x(t) but you only need x at a particular time.
So on the 2nd page you would end up with -(1/3)x3t + 3xt - (8/3)t ?
 
No - remember, the x terms are not constants in time.
You have to integrate the x terms wrt x.
 
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