Classification of Vector Bundles over Spheres

In summary, there is a bijective correspondence between K^k(S^n) and \pi_{n-1}(GL(k)), where K^k(S^n) denotes the isomorphism classes of rank k vector bundles over the sphere. This can be proven by considering the classifying space for vector bundles over the sphere and showing that two isomorphic bundles have homotopic classifying maps. This provides an elementary approach to the proof without involving the Grassmanian.
  • #1
zhentil
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This is a question from Hirsch's Differential Topology book: show that there is a bijective correspondence between
[tex]K^k(S^n) \leftrightarrow \pi_{n-1}(GL(k)) [/tex],
where [tex]K^k(S^n) [/tex] denotes the isomorphism classes of rank k vector bundles over the sphere. The basic idea is that any vector bundle over the sphere has a trivializing cover consisting of two open sets diffeomorphic to [tex]\textbf{R}^n[/tex]. The transition function of such a cover restricts to a map from the equator [tex]S^{n-1} \rightarrow GL(k)[/tex]. Moreover, vector bundles with homotopic classifying maps are isomorphic. However, the reverse inclusion is eluding me. Why must two isomorphic bundles over the sphere have homotopic classifying maps?

I've seen a proof of this involving writing the Grassmanian as a fiber bundle of orthogonal groups, and using the exact homotopy sequence to conclude that [tex]\pi_n(G_{3k,k}) \cong \pi_{n-1}(GL(k)) [/tex], but since Hirsch never mentioned that, it strikes me that there must be an elementary way of seeing this. Any ideas?
 
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  • #2


Hello,

Thank you for bringing up this interesting question from Hirsch's Differential Topology book. The proof you mentioned involving the Grassmanian as a fiber bundle of orthogonal groups is indeed one way to show the bijective correspondence between K^k(S^n) and \pi_{n-1}(GL(k)). However, there is indeed a more elementary approach that does not involve the use of the Grassmanian.

Firstly, let's recall the definition of the classifying space for vector bundles over a topological space X. This is a space BG such that there exists a bijective correspondence between isomorphism classes of rank k vector bundles over X and homotopy classes of maps from X to BG. In our case, we are interested in the classifying space for vector bundles over the sphere S^n, which is denoted by BS^n.

Now, let's consider the trivializing cover of a rank k vector bundle over S^n as mentioned in the forum post. This cover consists of two open sets diffeomorphic to \textbf{R}^n, and the transition function between these two open sets can be thought of as a map from the equator S^{n-1} to GL(k). This map is a homotopy classifying map for our vector bundle, since it captures the topological information of the bundle over the equator.

Now, suppose we have two isomorphic bundles over S^n. This means that there exists a diffeomorphism between the two bundles, which induces a homotopy equivalence between the corresponding classifying maps. This is because the diffeomorphism preserves the topological information of the bundle over each point on the equator. Therefore, the two bundles have homotopic classifying maps, and we have shown the reverse inclusion.

I hope this helps in understanding the bijective correspondence between K^k(S^n) and \pi_{n-1}(GL(k)). Please let me know if you have any further questions or if you would like me to elaborate on any specific part of the proof. Thank you.
 

1. What is a vector bundle?

A vector bundle is a mathematical construct that generalizes the notion of a vector space. It is a topological space that locally looks like a Cartesian product of a vector space with a base space, such as a sphere. Vector bundles are used to study the geometry and topology of spaces.

2. What is the importance of classifying vector bundles over spheres?

The classification of vector bundles over spheres is important because it helps us understand the structure of vector bundles and their relationship to other mathematical objects. It also has applications in other areas of mathematics, such as algebraic topology and differential geometry.

3. How are vector bundles over spheres classified?

Vector bundles over spheres are classified by their Chern classes, which are topological invariants that measure the curvature of the bundle. These classes can be used to determine the isomorphism classes of vector bundles over spheres.

4. Can vector bundles over spheres be classified in higher dimensions?

Yes, vector bundles over spheres can be classified in higher dimensions. In fact, the classification problem becomes more complicated as the dimension increases, and it is an active area of research in mathematics.

5. What are some applications of the classification of vector bundles over spheres?

The classification of vector bundles over spheres has applications in mathematical physics, such as in the study of gauge theories and string theory. It also has applications in algebraic geometry, where vector bundles are used to study algebraic varieties. Additionally, the classification has connections to other areas of mathematics, including topology, differential geometry, and representation theory.

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