Closed tube standing wave

AI Thread Summary
Standing waves in a closed tube produce a fundamental frequency based on the tube's length, calculated as v/4L. In an experiment with a 33.2 cm bottle, the expected frequency was 283 Hz, but spectral analysis revealed a fundamental frequency of 96 Hz with harmonics. This discrepancy is attributed to the bottle acting as a Helmholtz resonator rather than a simple closed-end pipe. Switching to a proper pipe confirmed the expected frequency, aligning with the Helmholtz resonant frequency calculation. The experiment highlights the importance of understanding the differences between resonator types in sound production.
exaramco
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Standing waves have a fundamental frequency equal to 4x the length of the pipe if the pipe is closed at one end and open at the other end.

So, blowing across the top of a 33.2 cm bottle should produce a fundamental frequency of v/4L or about 340/1.2= 283 hz. When I record the sound produced by this bottle and then run a spectral analysis (I have done this several times) sampling at both 1000 hz and 44khz I consistently get a fundamental frequency of 96 hz with harmonics at multiples of 96 hz. A closed end tube should produce only odd harmonics.

What is going on?
 
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A bottle is not a pipe.
A bottle often works as a Helmholtz resonator.
This is probably what happened in your experiment.
 
Right you are! I changed to a pipe and the spectrum came right on target. Thank you.
 
In fact, when I plugged in the equation for the resonant Helmholts frequency, it came at about 100 hz--just what I measured. Thanks again.
 
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