- #1
Matt Jacques
- 81
- 0
Oh boy, for some reason I'm just not getting this. I must be fouling up some really simple part. He just dives into problems without explaining the derivations and uses of the problems. Forgive my lack of knowledge on use of units.
My questions:
"A uniform line charge extends from x = -2.5 to x = 2.5 and charge density of 6.0 nC/m. a ) find the total charge
Ok, that's easy. That's just Q = 6.0 nC/m * .05 m = .3 * 10^-9
B) Find the electric field at 4.0 cm
The examples infer I should use:
E = kQ / (xp^2 - (1/2L)^2) where xp = (1/2)L
Is that the right formula?
Next question:
A 2 micro-coulomb charge is .2 m above the center of a square of sides .4 m. Find the flux through the square.
I found the electric field at the square with:
E = kQ/ r^2
E = (9*10^9)(2*10^-6) / (.2^2)
E = 450,000
Flux = E*A
Flux = (450,000)(.4^2) = 72,000
However, the book says 37700 ...
Next...
"The electric field at 250 m is 150 n/C and at 400 m it is 170 N/C. Calculate the volume charge density"
I'm just clueless here.
Any help is appreciated. I'll be back for more help soon :(
My questions:
"A uniform line charge extends from x = -2.5 to x = 2.5 and charge density of 6.0 nC/m. a ) find the total charge
Ok, that's easy. That's just Q = 6.0 nC/m * .05 m = .3 * 10^-9
B) Find the electric field at 4.0 cm
The examples infer I should use:
E = kQ / (xp^2 - (1/2L)^2) where xp = (1/2)L
Is that the right formula?
Next question:
A 2 micro-coulomb charge is .2 m above the center of a square of sides .4 m. Find the flux through the square.
I found the electric field at the square with:
E = kQ/ r^2
E = (9*10^9)(2*10^-6) / (.2^2)
E = 450,000
Flux = E*A
Flux = (450,000)(.4^2) = 72,000
However, the book says 37700 ...
Next...
"The electric field at 250 m is 150 n/C and at 400 m it is 170 N/C. Calculate the volume charge density"
I'm just clueless here.
Any help is appreciated. I'll be back for more help soon :(