Coefficient of friction and drunk driver

AI Thread Summary
A drunk driver in a 2400kg car collided with a 1200kg parked car, causing both to skid together for 25 meters before stopping. The effective coefficient of friction was measured at 0.70. The equation used to calculate the initial speed of the drunk driver was Mv^2 / 2 = (M+m)μg * S. The user calculated a speed of 7.246 m/s but was informed they neglected to include the acceleration due to gravity in their calculations. Correcting this oversight is essential for an accurate determination of the driver's speed before the collision.
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Homework Statement



A drunk driver in a 2400kg car plows into a 1200kg parked car with its brake set. Police measurements show that the two cars skid together a distance of 25m before stopping.

If the effective coefficient of friction is 0.70, how fast was the drunk going just before the collision?


Homework Equations



Mv^2 / 2 = (M+m)μg * S i used this equation

2400*v^2/2=(2400+1200)*.70*25m

and i got 7.246 for v

what did i do wrong?

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It looks to me like when you subbed in your values for the equation, you forgot acceleration due to gravity.
 
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