MHB Coefficient of Friction: Finding in a Factory

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In a factory scenario, a machine clamps a 4kg box with a total contact force of 100N from two identical clamps. To prevent the box from slipping, the minimum coefficient of friction required is calculated using the equation 40 = coefficient of friction × 100. This results in a coefficient of friction of 0.4. The discussion emphasizes the importance of a free body diagram in analyzing the forces involved. The calculations confirm that a coefficient of 0.4 is sufficient to keep the box secure.
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In a factory, a machine picks up a box by clamping it on both sides. The box of mass 4kg is held clamped on both sides by identical clamps with the contacts horizontal. The machine provides a contact force of 50N with each clamp. Find the minimum coefficient of friction between each clamp and the box for the box not to slip.
 
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have you sketched a free body diagram?

In the vertical direction ...

\[ \sum f_{s \, max} = mg \]
 
skeeter said:
have you sketched a free body diagram?

In the vertical direction ...

\[ \sum f_{s \, max} = mg \]
Yeah I did that. 40=coefficient of friction ×(50+50).
Coefficient of friction =0.4
 
skeeter said:
have you sketched a free body diagram?

In the vertical direction ...

\[ \sum f_{s \, max} = mg \]
Thank you so much!
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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