Coefficient of Friction: Finding in a Factory

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    Friction Mechanics
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SUMMARY

The discussion centers on calculating the minimum coefficient of friction required to prevent a 4kg box from slipping when clamped by two identical clamps applying a contact force of 50N each. The established formula used is \( \sum f_{s \, max} = mg \), leading to the conclusion that the coefficient of friction must be 0.4. A free body diagram was utilized to visualize the forces acting on the box, confirming the calculations. This analysis is crucial for ensuring the effective operation of machinery in a factory setting.

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Shah 72
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In a factory, a machine picks up a box by clamping it on both sides. The box of mass 4kg is held clamped on both sides by identical clamps with the contacts horizontal. The machine provides a contact force of 50N with each clamp. Find the minimum coefficient of friction between each clamp and the box for the box not to slip.
 
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have you sketched a free body diagram?

In the vertical direction ...

\[ \sum f_{s \, max} = mg \]
 
skeeter said:
have you sketched a free body diagram?

In the vertical direction ...

\[ \sum f_{s \, max} = mg \]
Yeah I did that. 40=coefficient of friction ×(50+50).
Coefficient of friction =0.4
 
skeeter said:
have you sketched a free body diagram?

In the vertical direction ...

\[ \sum f_{s \, max} = mg \]
Thank you so much!
 

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