Coefficient of Friction: Finding in a Factory

  • Context: MHB 
  • Thread starter Thread starter Shah 72
  • Start date Start date
  • Tags Tags
    Friction Mechanics
Click For Summary

Discussion Overview

The discussion revolves around calculating the minimum coefficient of friction required to prevent a box from slipping when clamped by a machine in a factory setting. The context includes a specific scenario involving forces acting on the box and the application of frictional concepts.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents a scenario involving a 4kg box clamped by two identical clamps applying a contact force of 50N each, seeking to find the minimum coefficient of friction.
  • Another participant suggests sketching a free body diagram and notes the balance of forces in the vertical direction, indicating that the maximum static friction must equal the weight of the box.
  • A later reply confirms the use of the free body diagram and calculates the coefficient of friction as 0.4, based on the forces involved.
  • Another participant expresses gratitude for the assistance provided in the discussion.

Areas of Agreement / Disagreement

Participants generally agree on the approach of using a free body diagram and the calculations involved, but there is no explicit consensus on the correctness of the calculated coefficient of friction.

Contextual Notes

The discussion does not clarify any assumptions regarding the conditions under which the coefficient of friction is calculated, nor does it address potential variations in the forces applied or the nature of the surfaces in contact.

Shah 72
MHB
Messages
274
Reaction score
0
In a factory, a machine picks up a box by clamping it on both sides. The box of mass 4kg is held clamped on both sides by identical clamps with the contacts horizontal. The machine provides a contact force of 50N with each clamp. Find the minimum coefficient of friction between each clamp and the box for the box not to slip.
 
Mathematics news on Phys.org
have you sketched a free body diagram?

In the vertical direction ...

\[ \sum f_{s \, max} = mg \]
 
skeeter said:
have you sketched a free body diagram?

In the vertical direction ...

\[ \sum f_{s \, max} = mg \]
Yeah I did that. 40=coefficient of friction ×(50+50).
Coefficient of friction =0.4
 
skeeter said:
have you sketched a free body diagram?

In the vertical direction ...

\[ \sum f_{s \, max} = mg \]
Thank you so much!
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
5
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K