MHB Coefficient of Friction: Finding in a Factory

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In a factory scenario, a machine clamps a 4kg box with a total contact force of 100N from two identical clamps. To prevent the box from slipping, the minimum coefficient of friction required is calculated using the equation 40 = coefficient of friction × 100. This results in a coefficient of friction of 0.4. The discussion emphasizes the importance of a free body diagram in analyzing the forces involved. The calculations confirm that a coefficient of 0.4 is sufficient to keep the box secure.
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In a factory, a machine picks up a box by clamping it on both sides. The box of mass 4kg is held clamped on both sides by identical clamps with the contacts horizontal. The machine provides a contact force of 50N with each clamp. Find the minimum coefficient of friction between each clamp and the box for the box not to slip.
 
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have you sketched a free body diagram?

In the vertical direction ...

\[ \sum f_{s \, max} = mg \]
 
skeeter said:
have you sketched a free body diagram?

In the vertical direction ...

\[ \sum f_{s \, max} = mg \]
Yeah I did that. 40=coefficient of friction ×(50+50).
Coefficient of friction =0.4
 
skeeter said:
have you sketched a free body diagram?

In the vertical direction ...

\[ \sum f_{s \, max} = mg \]
Thank you so much!
 
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