Coefficient of Kinetic Friction

AI Thread Summary
The discussion focuses on calculating the coefficient of kinetic friction for a crate of bananas sliding across a floor. The crate starts with a speed of 4.2 m/s and travels 6.0 m before stopping, leading to the calculation of acceleration using the equation a = (vf^2 - v0^2) / (2Δx). The calculated acceleration is 1.47 m/s², and the user derives a mass ratio of 0.15 for the coefficient of kinetic friction. The user seeks confirmation of this result, which is acknowledged as correct by others in the thread. The conversation also includes a minor technical issue regarding post formatting.
Medgirl314
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Homework Statement



A crate of bananas has an initial speed of 4.2 m/s2. It slides across a floor, traveling 6.0m before coming to a stop. Find the coefficient of kinetic friction between the crate and the floor.

Homework Equations


Fnet=ma
v2=v02+2aΔx



The Attempt at a Solution



v=4.2 m/s
x=6.0 m
vf=0
Δx=6.0 m

a=v2-v02/2x
a=0-17.64 m/s2/12 m = 1.47m/s2
MN=ma
mg=a
mg=a/g
m=1.47 m/s2/9.8m/s2=.15

For a final answer of .15. This seems correct to me, but could someone please confirm?

Sorry about the doubled template, I don't know how to get rid of it without messing up my post! Any ideas? :smile:


 
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