Coefficient of static friction problem

AI Thread Summary
The discussion revolves around calculating the minimum coefficient of static friction required to prevent slipping in a carnival "Rotor-ride." The problem involves a cylindrical room with a radius of 5.0 m and a rotation frequency of 0.60 revolutions per second. The participant, Ryan, successfully calculates the velocity and acceleration but struggles to incorporate the friction coefficient into his solution. A key equation provided is u (coefficient of static friction) = [(4π²)(f²)(r)]/g, which helps relate the forces involved. The conversation emphasizes the importance of balancing forces in both the x-axis and y-axis to solve the problem effectively.
rykirk
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Hey guys,

I was wondering if you could help me out with the following problem...

In a "Rotor-ride" at a carnival, people pay money to be rotated in a vertical cylindrically walled "room". If the room radius is 5.0 m and the rotation frequency is .60 revoloutions per second when the floor drops out, what is the minimum coefficient of static friction so that people will not slip down.

I keep getting stuck in the same place...I have calculated the velocity using the formula for circular motion that states v=(2*pi*r)/T, getting (10*pi)/2 and could easily get the acceleration of the ride by squaring the velocity and dividing by the radius..but I'm not 100% sure what to do after that. I know I need an equation in which the mass will cancel out on both sides, but I'm not sure how to tie the friction coefficient into the problem. :frown:

Any help would be greatly appreciated

Thanks alot,

Ryan
 
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Remember in the cyclone the cetripetal force will be the normal force, (forces on x-axis) and on the y-axis we got the friction force pointin up and the weight pointing down.

Also a hint F_{f} = \mu N
 
perhaps the equation you are looking for is

u (coeffi of static friction)= [(4pi^2)(f^2)(r)]/g
 

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