Coefficient of static friction

AI Thread Summary
To find the coefficient of static friction for an apple crate weighing 49N and accelerating at 0.5m/s² with a 20N force applied at 19 degrees, the equations of motion must be set up correctly. The net force in the x-direction is influenced by the applied force, while the y-direction accounts for the normal force and weight. Initial calculations yielded a coefficient of 0.386, but after correcting for equilibrium conditions (setting fx and fy to zero), the correct value of 0.445 was confirmed. This highlights the importance of ensuring all forces are balanced when dealing with static friction problems. Properly applying these principles leads to accurate results in physics calculations.
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An apple crate with weight of 49N accelerates at 0.5m/s2 along a horizontal a force of 20N apllied above the horizontal at 19 degrees is required to bring the crate on the verge of motion. Find the coefficient of static friction between the crate and the surface.

-usn+20 cos 19 x direction
N+W+20 cos 19 y direction

F=ma F=5x0.5
F=2.5

don't know what to do next..please help
 
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I did it exactly the way I did the other problem but according to the book the answer should be 0.445 but I am getting 0.386
 
i don't know what I am doing wrong I don't thnik the book is wrong it says 0.445 and I got 0.386 like 4 times in a row
 
I got .386 too. But that is not to say that I didnt do anything wrong either, but it is a good sign we both got the same answer.
 
I redid the question and I got 0.445 I forgot to set fx and fy equal to zero because the crate is not in motion it is on "the verge of motion"
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
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