Collision- Am I thinking about this the right way?

AI Thread Summary
A front collision between two identical cars results in total kinetic energy being transformed into deformation, making it highly destructive for both vehicles. In contrast, when a car collides with a mountain wall, the vast mass of the mountain absorbs most of the car's kinetic energy, resulting in less damage to the car. The discussion highlights that inelastic collisions lead to equal energy transfer between colliding objects, while the significant mass difference in the second scenario means the mountain remains largely unaffected. Ultimately, the conclusion is that hitting a mountain wall is less destructive to the car than a collision with another car at the same speed. The analysis emphasizes the importance of considering momentum conservation and reference frames in understanding collision dynamics.
Oldblood
Messages
16
Reaction score
0

Homework Statement


Whats more destructive? A front collision between 2 identical cars, or 1 car with the same speed but driving into a mountainwall?


Homework Equations


Equations for conservation of energy and momentum.


The Attempt at a Solution


Hi guys, I am just wondering if I am thinking about this the right way or if there are any errors in my reasoning? For the front collision. The 2 cars will have a kinetic energy of 0.5mv^2 each. Let's assume the collision is totally Inelastic. Thus no kinetic energy is left. Due to symmetry the kinetic energy is transformed equally into both cars deforming them equally. So the total energy that had a destructive act on 1 car is 0.5mv^2. Now to the other case. I am going to think about this as a collision between a very large and very small object, where the large object is at rest. So the total energy now is 0.5mv^2. Since we now have 2 different masses, where they both are not at rest, we have a net momentum. So assuming the car totally stops it must transfer some of its kinetic energy to the large object, because if not the total momentum would be 0 and then it wouldn't be conserved since we had a net momentum before the collision. This means that the whole package of 0.5mv^2 does not go all the way to deformation, but some of it must go to transfer kinetic energy to the larger object, thus the impact is less destructive. This isn't really my homework, it was just a discussion I had with a friend.

Conclusion: You would rather hit a mountain wall then a front collision with the same speed (regarding damage on the car and in an ideal situation like this)
 
Last edited:
Physics news on Phys.org
Heh. When you're dealing with such enormous differences in masses (Car versus the Earth! now in theaters!) one often finds oneself dealing with near infinities or near neglibililities and falling into false assumptions about them.

In such cases it's often instructive to make a change of reference frame to get rid of the seeming paradoxes. Here you can switch to a center of momentum frame. In this frame, the mountain (attached to the whole Earth) and the car have equal and opposite momenta, so that the total momentum for the system is zero both before and after the collision. Problem solved.

With the great mass discrepancy between the car and the Earth, you'll find that the center of momentum frame looks an awful lot like the original frame of reference...the details being a good many decimal places down and to the right.
 
I saw this on MythBusters. :smile:

Assuming a totally inelastic collision, there is equal energy transfer between both cars. Similarly because of the disparity in mass of the mountain and the car, whatever pitiful amount of kinetic energy is transferred by the car into the mountain, the mountain remains unmoved (absorbing all of the energy).

So, the answer to "which collision is more destructive" really boils down to this:

Which would you rather have in your face: rocks (from the mountain), or glass (from the other car's windshield)?

 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top