Collision and conservation of P

AI Thread Summary
The discussion focuses on a physics problem involving the conservation of momentum during a collision between two balls. Ball A, with a mass of 1 kg, rolls west at 3 m/s and collides with a stationary ball B, which has a mass of 2 kg. After the collision, ball A moves south at 2 m/s, leading to the calculation of ball B's momentum and velocity. Using the conservation of momentum equation and vector analysis, it is determined that ball B has a momentum of 3.6 kgm/s at an angle of 33.7 degrees north of west, resulting in a velocity of 1.8 m/s at the same angle. The solution is confirmed to be correct.
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Homework Statement


A ball (A) is rolling west at 3m/s and has a mass of 1kg. Another ball (B) has a mass of 2kg and is stationary. After a collision, ball A moves south at 2 m/s. Calculate the momentum and velocity of ball B after the collision.

Homework Equations


Pa(initial)=Pa(final)+Pb(final
P=m x v
a2+b2=c2


The Attempt at a Solution


Pa(initial)=1kg(3m/s W)= 3kgm/s W
Pa(final)=1kg(2m/s S)= 2kgm/s S
Pa(initial)-Pa(final)=Pb(final)
a vector diagram gives me a right triangle. Pythagoras gives me c=Pb(final) as 3.6kgm/s
33.7 degrees North of West.
Pb=m x v
3.6kgm/s 33.7degrees north of west /2 kg= vb
vb= 1.8 m/s 33.7 degrees north of west.
Is this correct?
 
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Absolutely.
 
Thank you
 
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