Collision detection between a moving circle and stationary point

ZippyDee
Messages
11
Reaction score
0
I'm trying to figure out the best way to find a collision between a moving circle and a stationary line segment. I have the x and y of the point, and the x, y, radius, x velocity, and y velocity of the circle.

//Edit:
I tried using the equation of a circle with the origin at the point (P) and a radius equal to that of the original circle, and then solving that for x, substituting the equation for the line of motion of of the ball in place of y:

m=(ball.yVelocity)/(ball.xVelocity)
b=ball.y-ball.x*m
r2=((mx+b)-Py)2+(x-Px)2

I multiplied it all out and simplified it to standard form. Then I collected like terms and came up with these variables

A=m2+1;
B=2*m*b-2*m*Py-2*Px;
C=b2-2*b*Py+Py2+Px2;

Then I used the quadratic formula to find the intercepts

That should work, but it doesn't...
 
Last edited:
Mathematics news on Phys.org
Wow...never mind, I am an idiot...I forgot to subtract r2 before collecting terms!
 
Oh...but this doesn't work if the circle has an x velocity of 0...How do I deal with that?
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
Back
Top