Collision of Balls - Coefficient of Restitution

  • Thread starter Thread starter prateek_34gem
  • Start date Start date
  • Tags Tags
    Balls
AI Thread Summary
In the discussion about the collision of three balls, a third ball collides with two stationary equal balls, which remain at rest post-impact. The coefficient of restitution is being calculated, with options provided for the correct value. The user attempted to solve the problem using conservation of momentum and the coefficient of restitution equations but arrived at an incorrect answer of 1/2. The correct coefficient of restitution is determined to be 2/3, raising questions about the accuracy of the provided answer in the textbook. The focus remains on understanding the dynamics of the collision and the application of relevant physics principles.
prateek_34gem
Messages
15
Reaction score
0

Homework Statement



Two equal balls are in contact on a table and are in equillibrium. A third ball collides with them simultaneously, symetrically and remains at rest after the impact. The coefficient of restitution is :

A)2/3
B)3/2
C)1/3
D)1/2

Homework Equations





The Attempt at a Solution


i hav tried by combining the masses and velocities of the two balls at rest then found e. like the collision of two bodies ( considering two bodies as one ) .
 
Physics news on Phys.org
You have 2 equations that you would satisfy don't you?

Conservation of momentum which gives you the relationship between the initial velocity of the first ball and the final velocity of the second 2.

Then you have the equation for the coefficient of restitution that relates the before and after velocities of the 2 bodies. (This is simplified by the fact that before the collision only 1 was in motion. And after the collision the first becomes stationary.)
 
but there are two balls lying at rest do i hav to consider the motion of only one of thm or take them whole as one ?
 
Last edited:
i hav got e=1/2
but thts wrong ans . Correct ans . is 2/3
is ans given in book wrong or i am wrong ??
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top