Colombs,Amps,Volts,and Watts. HELP

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A car battery rated at 250 amp-hours indicates the charge capacity, not energy or power. The calculation of coulombs produced in one hour is correct, resulting in 900,000 coulombs. However, this does not directly provide information about energy in joules or voltage. The confusion arises from equating the number of electrons with total energy, which is incorrect. Amp-hours specifically measure charge, as amps represent coulombs per second.
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Colombs,Amps,Volts,and Watts. HELP!

Homework Statement



A given car battery is rated at 250 amp-hours. Does this rating indicate the amount of energy, power, charge, voltage, or current that can be drawn from the battery? Explain.

Homework Equations



Coulombs, Amps, Volts, Watts.

The Attempt at a Solution



I first calculated the coulombs that this battery produces in one hour. That turned out to be 250amp-hours X 3600seconds= 900,000.

Is this the furthest that I can get?? I am really stumped because I thought I could get more than just the number of coulombs. I tried finding out how many electrons pass through (2.25x10^22) but it seems like I cannot learn joules or voltage by knowing how many total electrons a battery is capable of dispensing.

I guess my problem is that I am equating the total number of electrons as a sort of total amount of energy. This is wrong?:cry:
 
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Your calculation has the right dimensions and is correct. But the 3600 is not seconds, it's just a number to convert the hours to seconds.

Amp-hours is charge because amp=Coulomb/s.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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