COM vs Lab Total energy discrepency

physmurf
Messages
26
Reaction score
0
I am reading from the book, "Nuclear Reactor Theory", by Lamarsh. I have run across an idea that I am struggling to understand:

It states that for a neutron that scatters elastically with a nucleus, the Energy in the Center of Mass (COM) frame of reference will always be slightly less than the total energy in the lab frame of reference.

For some reason I don't like this. Sure I can follow the mathematics and the explanation, but it doesn't seem right that the total energy would be the same. When I contacted my professor about this, he indicated that this is merely a classical idea. However, for some reason, this just doesn't jive with what I think should be going on.

Anybody have any conceptual explanations on why this is true?

Thanks
 
Physics news on Phys.org
Relativistic energy of any system in any reference frame is given by

E = \sqrt{M^2c^4 + \mathbf{P}^2c^2}...(1)

where \mathbf{P} is the total momentum and M is the rest mass, which is independent on the reference frame. In the center-of-mass frame the total momentum is zero, so the energy is E = Mc^2, which is lower than in any other reference frame (where the total momentum is non-zero).

So, the reason for the excess energy in the lab frame is the fact that the system (neutron + nucleus) has a non-zero momentum.

Eugene.
 
physmurf said:
It states that for a neutron that scatters elastically with a nucleus, the Energy in the Center of Mass (COM) frame of reference will always be slightly less than the total energy in the lab frame of reference.
...
For some reason I don't like this. Sure I can follow the mathematics and the explanation, but it doesn't seem right that the total energy would be the same.
I guess I don't get what's bugging you. The total energy will always be less in the COM frame.

(Looks like Eugene already answered.)
 
Doc Al said:
...

I guess I don't get what's bugging you. The total energy will always be less in the COM frame.

(Looks like Eugene already answered.)

Intuitively I would think that the total energy of the system should be the same no matter what frame of reference you are in... However, that is where my misconception lies...Energy is not always going to be the same in every reference frame!

I apologize for the stupid question. I appreciate your responses.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!
Back
Top