Combining Multiple Rules for Error Propagation

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Homework Help Overview

The discussion revolves around calculating the kinetic energy of an object with given mass and speed, including the estimation of uncertainty in the kinetic energy using error propagation techniques.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply exponent error propagation to the kinetic energy formula but questions how to incorporate the multiplication of mass and speed squared. Some participants suggest considering the product rule for error propagation, while others clarify the distinction between correlated and uncorrelated variables in error analysis.

Discussion Status

Participants are exploring different methods for error propagation and discussing the application of relevant equations. There is acknowledgment of the need to combine rules effectively, and some guidance has been provided regarding the product rule and the treatment of correlated versus uncorrelated variables.

Contextual Notes

The original poster expresses uncertainty about their approach and seeks clarification on combining different error propagation rules. There is a mention of specific values and uncertainties for mass and speed, which are central to the calculations being discussed.

ELLE_AW
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Homework Statement


  1. An object of mass m=2.3±0.1kg moves at a speed of v=1.25±0.03m/s. Calculate the kinetic energy (K=1/2mv2) of the object and estimate the uncertainty δK?

Homework Equations


- Addition error propagation--> z = x + y and the Limit error--> δz = δx + δy

- Exponent error propagation --> z = xn and the Limit Error --> δz = nxn-1(δx)

- K = 1/2mv2

The Attempt at a Solution



This is what I attempted, but I really don't think it's right. I basically just included the exponent error propagation, but how does the multiplication of mv2 get incorporated?

- K = ½ mv2 = ½ (2.3kg)(1.25m/s)2 = 1.7969 kg m2 s-2 = 1.8 J

- Uncertainty of K = (m)2v1(δv) = (2.3)(2)(1.25)(0.03) = 0.1725 = 0.17
How do I combine these two rules when calculating the uncertainty of the kinetic energy?

 
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ELLE_AW said:
Relevant equations
You seem to be missing the product rule:
If z=xy then δz/z=δx/x+δy/y
 
ELLE_AW said:
Addition error propagation--> z = x + y and the Limit error--> δz = δx + δy
This is error propagation for correlated variables x and y. If your variables are uncorrelated, they should be added in quadrature, i.e.,
$$
\delta z^2 = \delta x^2 + \delta y^2.
$$
The same is true for uncorrelated relative errors in the case of a product.
 
Got it, thank you!
 

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