Comet Elliptical Orbits Question

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Comet Halley moves in an elliptical orbit, with its closest approach to the sun recorded at 8.79 x 10^7 km and a speed of 54.6 km/s in 1986. To find its speed when crossing Neptune's orbit in 2006, the conservation of energy approach is recommended instead of the initial momentum equation, as it only applies under specific conditions. The relevant formula involves kinetic and potential energy, indicating that the potential energy gained equals the kinetic energy lost. The mass of the comet and the sun should be considered in the calculations. Understanding these principles will lead to the correct solution for the comet's speed at Neptune's orbit.
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Homework Statement


Comets move around the sun in very elliptical orbits. At its closet approach, in 1986, Comet Halley was 8.79 x 10^7 km from the sun and moving with a speed of 54.6 km/s.

What was the comet's speed when it crossed Neptune's orbit in 2006?

Homework Equations



Mv1r1=Mv2r2

The Attempt at a Solution



What I did was use the equation above, and solve for v2. But it says I'm wrong. Any Suggestions?
 
Last edited:
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What did you use for r2?
What did you get for v2?
 
For r2, I use the radius from Neptune to the sun.
 
Oh I see ... excuse me, didn;t read it properly.
That formula should be:

##\vec{r}_1\times m\vec{v}_1=\vec{r}_2\times m\vec{v}_2##

At Neptune's orbit, the velocity won't be tangential to the radius.
 
Chaso said:

Homework Statement


Comets move around the sun in very elliptical orbits. At its closet approach, in 1986, Comet Halley was 8.79 x 10^7 km from the sun and moving with a speed of 54.6 km/s.

What was the comet's speed when it crossed Neptune's orbit in 2006?

Homework Equations



Mv1r1=Mv2r2

The Attempt at a Solution



What I did was use the equation above, and solve for v2. But it says I'm wrong. Any Suggestions?

The formula you've chosen would apply when the velocities are both perpendicular to the radii, say at perihelion and at aphelion. Here this holds true for only one of the given points (the closest approach).

Instead, consider a conservation of energy approach.
 
gneill said:
The formula you've chosen would apply when the velocities are both perpendicular to the radii, say at perihelion and at aphelion. Here this holds true for only one of the given points (the closest approach).

Instead, consider a conservation of energy approach.
So use K2 + U2 = K1 + U1

expansion to:
(1/2)(Mc)(v2^2) + -(G)(Me)(Mc)/(R) = (1/2)(Mc)(v1^2) + -(G)(Me)(Mc)/(R2)

R = Distance of neptune from sun
R2 = 8.79 x 10^7

Is this what I do?
 
Last edited:
Mc is the mass of the comet and Me is the mass of the body the comet is orbiting?

Note: another way thinking about it is "potential energy gained equals kinetic energy lost".
 

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