Commutator of Position and Energy

Click For Summary
SUMMARY

The discussion centers on the commutation relationship between the energy operator, defined as \imath \frac{h}{2\pi}\frac{\partial}{\partial t}, and the position operator x in non-relativistic quantum mechanics. It is established that while the energy operator may appear to commute with position, the Hamiltonian generally does not, leading to the conclusion that simultaneous eigenstates of these operators do not exist. The confusion arises from conflating the time-dependent energy operator with the Hamiltonian, which is not valid in the context of the Schrödinger equation.

PREREQUISITES
  • Understanding of non-relativistic quantum mechanics
  • Familiarity with the Schrödinger equation
  • Knowledge of operator theory in quantum mechanics
  • Concept of commutation relations in quantum mechanics
NEXT STEPS
  • Study the implications of the Schrödinger equation on state vectors
  • Research the role of the Hamiltonian in quantum mechanics
  • Learn about commutation relations and their significance in quantum mechanics
  • Explore the concept of velocity operators and their relation to energy and position
USEFUL FOR

Students and professionals in quantum mechanics, physicists exploring operator theory, and anyone interested in the foundational principles of quantum mechanics and operator commutation.

meichenl
Messages
25
Reaction score
0
This is a question about simple non-relativistic quantum mechanics in one dimension.

If the energy operator is [tex]\imath \frac{h}{2\pi}\frac{\partial}{\partial t}[/tex], then it would appear to commute with the position operator [tex]x[/tex]. Then, if the energy and position operators commute, I ought to be able to find simultaneous eigenstates of them.

However, it is clear that in general the Hamiltonian does not commute with [tex]x[/tex], and in general these two operators do not have any simultaneous eigenstates.

What is wrong with my thinking? Does it make sense to think of [tex]\imath \frac{h}{2\pi} \frac{\partial}{\partial t}[/tex] as the energy operator, and is that supposed to be the same as the Hamiltonian? Am I running into a problem because I am thinking on the one hand of a time-independent problem and on the other of a time-dependent one? Alternatively, is it incorrect to state that any two operators which commute must have simultaneous eigenstates?

Thank you,
Mark
 
Physics news on Phys.org
Time derivative is not a valid operator in the Hilbert space, and its commutator with x does not make sense. Normally, vectors in the Hilbert space do not depend on time. The time dependence arises only when you look at the state from different (time displaced) reference frames.

Schroedinger equation does not say that "the time derivative and the Hamiltonian are equivalent operators" It says: "the time derivative of the state vector is equal to the action of the Hamiltonian on the state vector".
 
meichenl said:
[...] if the energy and position operators commute [...]

[H,X] is usually taken to be a velocity operator.
I.e., energy and position don't commute in general.
 

Similar threads

  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
4K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 18 ·
Replies
18
Views
4K