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Compare y=Cos(x) and transformation HELP

  1. Sep 12, 2005 #1
    How does the graph [tex] y=-3 \cos (2\theta+ \frac {\pi} {4}) +3 [/tex] Differ from the graph of [tex] y=\cos\theta [/tex]

    I think this graph is different because it has a vertical stretch by a factor of 3 and is translated upwards 3 units but im not sure how to rearrange this to find the horizontal translation and the horizontal compression/stretch

    Could someone please help me out! THANKS :smile:
  2. jcsd
  3. Sep 12, 2005 #2
    A computer program can be helpful - enjoy changing parameters and understanding the corresponding changes of the graph.
  4. Sep 12, 2005 #3
    Let's suppose that theta is replace by t.
    in cos(2t + pi/4) can be written cos2(t+pi/8) that you can compare with cosa(t-h) where the parameter h gives you how many units the curve is translate to the right (when h >0) or to the left (when h<0)
    Now you can see that in your problem h = -pi/8, so the translation is to the left pi/8 units. The parameter a = 2 tells you the number of times it osccillates in the intervall length of 2 pi; in the problem you have 2 complete oscillations in an intervall length of 2 pi.
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