Comparing Deck Beams: 4"x10" vs. 4"x12" with Same Material and Load Conditions

  • Thread starter Thread starter walt88
  • Start date Start date
  • Tags Tags
    Beam
AI Thread Summary
The discussion centers on comparing the strength of two deck beams: a 4"x10" beam at 8' long and a 4"x12" beam at 12' long, both made of the same material and subjected to identical load conditions. Calculations reveal that the moment of inertia for the 4"x10" beam is 333.33 in^4, while the 4"x12" beam has a moment of inertia of 576 in^4. Despite the larger beam being stiffer, the shorter beam exhibits less deflection and is stronger under the same load, being 1.953 times stiffer and 1.042 times stronger in terms of stress. The discussion emphasizes that comparing beam strengths requires considering both the section modulus and the effects of beam length on stress and deflection. Ultimately, the shorter beam is determined to be the stronger option for the given load conditions.
walt88
Messages
1
Reaction score
0
This is for a deck:

Which beam is stronger?

A) a beam with cross-section dimensions 4"x10" and 8' long
B) a beam with cross-section dimensions 4"x12" and 12' long

Both beams are same material and are both simply supported at the ends. Same load type (either concentrated or distributed doesn't really matter) and same load location.


Here are my thoughts:
Moment of inertia for beams: A: 333.33 in^4; B: 576 in^4
Lengths of beams: A: 96 in; B: 144 in

Using the equation for a concentrated load at the center: P = (deflection*48*E*I)/(L^3)
The deflection of beam A is about half the deflection of B. Does this mean A is stronger with the given loads?
 
Engineering news on Phys.org
A good way to compare is to use what is known as the section modulus (usually given the symbol Z or S)

Values of Z are often tabulated in structural tables, but can easily be computed as the ratio of the moment of intertia to the distance from the neutral axis to the edge of the beam (c).


Z = \frac{I}{c}

In the case of a rectangular beam c=h/2 where h is the height of the beam.

If M is the maximum moment on the beam ( computed directly from the loads and geometry of the beam) and f is the allowable maximum stress in the material, a particularly simple equation then results.


Z = \frac{M}{f}

does this help?
 
walt88 said:
Does this mean beam A is stronger with the given loads?
walt88: Yes, that is correct. If both beams have exactly the same material strength, beam A is 1.953 times stiffer than beam B with respect to (w.r.t.) deflection, and 1.042 times stronger than beam B w.r.t. stress.
 
Don't confuse member strength and stiffness with performance under load. The larger section is both stronger and stiffer, but because it is on a longer span, it may be more highly stressed and may deflect more under the same load.
 
It's true, with some quick calcs it looks like the stress under the same load will be 4.2% higher in the longer beam. In other words, the shorter beam is stronger under the same load.

It takes more than just the section modulus to compare beam strengths when the length changes too...
 

Attachments

It takes more than just the section modulus to compare beam strengths when the length changes too

Yes indeed, but this is taken care of in the comparison to the section modulus to the actual applied moment.
 
Hi all, I have a question. So from the derivation of the Isentropic process relationship PV^gamma = constant, there is a step dW = PdV, which can only be said for quasi-equilibrium (or reversible) processes. As such I believe PV^gamma = constant (and the family of equations) should not be applicable to just adiabatic processes? Ie, it should be applicable only for adiabatic + reversible = isentropic processes? However, I've seen couple of online notes/books, and...
Thread 'How can I find the cleanout for my building drain?'
I am a long distance truck driver, but I recently completed a plumbing program with Stratford Career Institute. In the chapter of my textbook Repairing DWV Systems, the author says that if there is a clog in the building drain, one can clear out the clog by using a snake augur or maybe some other type of tool into the cleanout for the building drain. The author said that the cleanout for the building drain is usually near the stack. I live in a duplex townhouse. Just out of curiosity, I...
I have an engine that uses a dry sump oiling system. The oil collection pan has three AN fittings to use for scavenging. Two of the fittings are approximately on the same level, the third is about 1/2 to 3/4 inch higher than the other two. The system ran for years with no problem using a three stage pump (one pressure and two scavenge stages). The two scavenge stages were connected at times to any two of the three AN fittings on the tank. Recently I tried an upgrade to a four stage pump...
Back
Top